What is the domain of sqrt(x^2+2x-8) ?

The domain of sqrt(x^2+2x-8) is x = 2

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domain of sqrt(x^2+2x-8)

domain

x^{2} + 2 x - 8

x \leq - 4 or x \geq 2

Interval Notation

(- \infty, - 4] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 2

The function domain

x \leq - 4 or x \geq 2

f (x) = \frac{2}{x ^{2} - 7 x + 10}

f (x) = lo g_{10} (2) (x + 1)

f (x) = \frac{( 2 x - 1 )}{x - 1}

\frac{t ( t - 3 )}{t - 2} + \frac{4 - t}{t - 2}

f (x) = \frac{x}{2 - x}

What is the domain of sqrt(x^2+2x-8) ?
The domain of sqrt(x^2+2x-8) is x<=-4\lor x>= 2