What is the domain of f(x)=(sqrt(x-4))/(x^2-25) ?

The domain of f(x)=(sqrt(x-4))/(x^2-25) is 4 5

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domain of f(x)=(sqrt(x-4))/(x^2-25)

domain

f (x) = \frac{x - 4}{x ^{2} - 25}

4 \leq x < 5 or x > 5

Interval Notation

[4, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

4 \leq x < 5 or x > 5

\frac{e ^{x}}{x - 1}

f (x) = x^{5} + x^{2} - 4

3 x + 8

f (x) = \frac{25 - x ^{2}}{ln ( 2 x - 3 )}

3 + x + 1

What is the domain of f(x)=(sqrt(x-4))/(x^2-25) ?
The domain of f(x)=(sqrt(x-4))/(x^2-25) is 4<= x<5\lor x>5