What is the domain of f(x)=(ln(9-x^2))/(e^x-1) ?

The domain of f(x)=(ln(9-x^2))/(e^x-1) is -3<x<0\lor 0<x<3

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domain of f(x)=(ln(9-x^2))/(e^x-1)

domain

f (x) = \frac{ln ( 9 - x ^{2} )}{e ^{x} - 1}

- 3 < x < 0 or 0 < x < 3

Interval Notation

(- 3, 0) \cup (0, 3)

Solution steps

Find positive values for logs:

- 3 < x < 3

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 3 < x < 0 or 0 < x < 3

f (x) = x + 4 + 2

\frac{x ^{3} + x + 8}{x ^{4} - 1}

f (x) = \frac{x + 2}{3 - x}

f (x) = \frac{1}{3 x - 4}

f (x) = \frac{1 - 3 x}{x - 1}

What is the domain of f(x)=(ln(9-x^2))/(e^x-1) ?
The domain of f(x)=(ln(9-x^2))/(e^x-1) is -3<x<0\lor 0<x<3