What is the domain of f(x)= 1/(sqrt(4.7x-5.3x^2)) ?

The domain of f(x)= 1/(sqrt(4.7x-5.3x^2)) is 0<x< 47/53

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domain of f(x)= 1/(sqrt(4.7x-5.3x^2))

domain

f (x) = \frac{1}{4.7 x - 5.3 x ^{2}}

0 < x < \frac{47}{53}

Interval Notation

(0, \frac{47}{53})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{47}{53}

Find undefined (singularity) points:

x = 0, x = \frac{47}{53}

Combine real regions and undefined points for final function domain

0 < x < \frac{47}{53}

f (x) = \frac{ln ( x + 3 )}{x ^{2} - 16}

f (x) = \frac{3}{x ^{2} - 8 x + 15}

f (x) = lo g_{5} (x - 2)

\frac{x ^{3} + 1}{x ^{2}}

f (x) = x + 4 x + 2

What is the domain of f(x)= 1/(sqrt(4.7x-5.3x^2)) ?
The domain of f(x)= 1/(sqrt(4.7x-5.3x^2)) is 0<x< 47/53