What is the domain of f(x)= 1/(sqrt(1.8x-3.6x^2)) ?

The domain of f(x)= 1/(sqrt(1.8x-3.6x^2)) is 0<x< 1/2

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domain of f(x)= 1/(sqrt(1.8x-3.6x^2))

domain

f (x) = \frac{1}{1.8 x - 3.6 x ^{2}}

0 < x < \frac{1}{2}

Interval Notation

(0, \frac{1}{2})

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{1}{2}

Find undefined (singularity) points:

x = 0, x = \frac{1}{2}

Combine real regions and undefined points for final function domain

0 < x < \frac{1}{2}

y = x^{2}

f (x) = \frac{x - 6}{x ^{2} - x - 2}

\frac{x - 2}{x + 1}

f (x) = lo g_{\frac{1}{3}} (2 x^{2} - 12 x + 22)

f (x) = \frac{5 - x}{x + 8}

What is the domain of f(x)= 1/(sqrt(1.8x-3.6x^2)) ?
The domain of f(x)= 1/(sqrt(1.8x-3.6x^2)) is 0<x< 1/2