What is the domain of f(x)=sqrt(1+ln(x)) ?

The domain of f(x)=sqrt(1+ln(x)) is x>= 1/e

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domain of f(x)=sqrt(1+ln(x))

domain

f (x) = 1 + ln (x)

x \geq \frac{1}{e}

Interval Notation

[\frac{1}{e}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e}

The function domain

x \geq \frac{1}{e}

- \frac{1}{2} x - 3

f (x) = 2 x^{2} + 5 x - 3

f (x) = \frac{ln ( 1 - x )}{x ^{3} + 2 x}

- x + 6

y = x^{2} - 2 x - 1

What is the domain of f(x)=sqrt(1+ln(x)) ?
The domain of f(x)=sqrt(1+ln(x)) is x>= 1/e