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Popular >

inverse of sin^2(θ)

Solution

inverse

sin^{2} (θ)

Solution

arcsin (θ), arcsin (- θ)

Solution steps

Solve for

sin (θ), y = sin^{2} (θ)

sin (θ) = y, sin (θ) = - y

sin (a) = b \Rightarrow a = arcsin (b)

arcsin (y), arcsin (- y)

Substitute

y = θ

arcsin (θ), arcsin (- θ)

Popular Examples

asymptotes of (x^2-5x+4)/(x^2-4)asymptotes

\frac{x ^{2} - 5 x + 4}{x ^{2} - 4}

domain of f(x)=sqrt(x-2)*1/(x+2)domain

f (x) = x - 2 \cdot \frac{1}{x + 2}

midpoint (-2,4),(-2,-4)midpoint

(- 2, 4), (- 2, - 4)

asymptotes of f(x)=(x^2-3x+8)/(x-2)asymptotes

f (x) = \frac{x ^{2} - 3 x + 8}{x - 2}

critical f(x)=12-6e^{-x}critical points

f (x) = 12 - 6 e^{- x}

Frequently Asked Questions (FAQ)

What is the inverse of sin^2(θ) ?
The inverse of sin^2(θ) is arcsin(sqrt(θ)),arcsin(-sqrt(θ))