What is the domain of sqrt(x^4-16) ?

The domain of sqrt(x^4-16) is x = 2

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domain of sqrt(x^4-16)

domain

x^{4} - 16

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = ln (x) - 1

\frac{x + 5}{x - 6}

\frac{1}{t}

x^{4} + 2 x^{3} + 2 x^{2} + 4 x

\frac{3 x ^{2}}{x ^{2} - 9}

What is the domain of sqrt(x^4-16) ?
The domain of sqrt(x^4-16) is x<=-2\lor x>= 2