What is the domain of x/(x^2+x-12) ?

The domain of x/(x^2+x-12) is x 3

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domain of x/(x^2+x-12)

domain

\frac{x}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

11 - x

t

y = \frac{x}{x ^{2} + 1}

\frac{x ^{2} - x}{x ^{2} - 1}

f (x) = \frac{x}{x - 1 - 1}

What is the domain of x/(x^2+x-12) ?
The domain of x/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3