What is the domain of (x^2)/(sqrt(x+1)) ?

The domain of (x^2)/(sqrt(x+1)) is x>-1

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domain of (x^2)/(sqrt(x+1))

domain

\frac{x ^{2}}{x + 1}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x > - 1

f (x) = lo g_{10} (8 - x)

f (x) = - 2 + 1 - x

f (x) = x^{2} + 12 x + 32

y = 4 x^{2} + 7 x - 19

ln (5 - t^{2})

What is the domain of (x^2)/(sqrt(x+1)) ?
The domain of (x^2)/(sqrt(x+1)) is x>-1