What is the domain of f(x)=((x^2+1))/((x^2-4)) ?

The domain of f(x)=((x^2+1))/((x^2-4)) is x 2

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domain of f(x)=((x^2+1))/((x^2-4))

domain

f (x) = \frac{( x ^{2} + 1 )}{( x ^{2} - 4 )}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = e^{x^{2} - 3} + (x^{2} - 4)^{\frac{5}{3}}

f (x) = 9 - \frac{2}{x}

6 x - 12

\frac{4}{x} - 5

f (x) = ∣ x ∣ + 3 x + 1

What is the domain of f(x)=((x^2+1))/((x^2-4)) ?
The domain of f(x)=((x^2+1))/((x^2-4)) is x<-2\lor-2<x<2\lor x>2