What is the domain of (x-1)/(x^2+4x-5) ?

The domain of (x-1)/(x^2+4x-5) is x 1

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domain of (x-1)/(x^2+4x-5)

domain

\frac{x - 1}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Interval Notation

(- \infty, - 5) \cup (- 5, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

- lo g_{5} (x + 2)

f (x) = \frac{2}{x ^{2} - x - 6}

f (x) = \frac{x - 9}{x ^{2} - 3 x}

f (x) = \frac{x ^{2}}{x + 5}

4 cos (x) + 1, 0 \leq x \leq 2 π

What is the domain of (x-1)/(x^2+4x-5) ?
The domain of (x-1)/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1