What is the domain of f(x)=(ln(x+2))/(x-1) ?

The domain of f(x)=(ln(x+2))/(x-1) is -2 1

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domain of f(x)=(ln(x+2))/(x-1)

domain

f (x) = \frac{ln ( x + 2 )}{x - 1}

- 2 < x < 1 or x > 1

Interval Notation

(- 2, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x > - 2

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 2 < x < 1 or x > 1

f (x) = - ∣ x ∣ + 1

f (x) = \frac{x + 4}{x - 3}

f (x) = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 2 x + 1

f (x) = - lo g_{10} (x)

f (x) = 2 [x], - 2 \leq x \leq 2

What is the domain of f(x)=(ln(x+2))/(x-1) ?
The domain of f(x)=(ln(x+2))/(x-1) is -2<x<1\lor x>1