What is the domain of f(x)= 1/2 sqrt(x+2) ?

The domain of f(x)= 1/2 sqrt(x+2) is x>=-2

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domain of f(x)= 1/2 sqrt(x+2)

domain

f (x) = \frac{1}{2} x + 2

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

2 x^{2} + 4 x - 6

\frac{x ^{2} - 81}{x ^{2} - 64}

12 - x + 3

f (x) = \frac{x}{x ^{2} + 8 x + 15}

f (x) = \frac{x - 5}{x ^{2} - 5 x + 6}

What is the domain of f(x)= 1/2 sqrt(x+2) ?
The domain of f(x)= 1/2 sqrt(x+2) is x>=-2