What is the domain of f(x)=sqrt(x^2-4x) ?

The domain of f(x)=sqrt(x^2-4x) is x = 4

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domain of f(x)=sqrt(x^2-4x)

domain

f (x) = x^{2} - 4 x

x \leq 0 or x \geq 4

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

The function domain

x \leq 0 or x \geq 4

4 x - 5 y = - 1

f (x) = 9 - 5 x

3 (\frac{x - 12}{3}) + 12

f (x) = 2 x^{3} - 1

f (x) = \frac{4 x - 20}{x - 5}

What is the domain of f(x)=sqrt(x^2-4x) ?
The domain of f(x)=sqrt(x^2-4x) is x<= 0\lor x>= 4