What is the domain of f(x)=sqrt(((1-x))/x) ?

The domain of f(x)=sqrt(((1-x))/x) is 0<x<= 1

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domain of f(x)=sqrt(((1-x))/x)

domain

f (x) = \frac{( 1 - x )}{x}

0 < x \leq 1

Interval Notation

(0, 1]

Solution steps

Find non-negative values for radicals:

0 < x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

0 < x \leq 1

\frac{6 x}{( x - 5 ) ( x - 9 )}

f (x) = 5^{x} - 3

f (x) = \frac{1}{x - 4}

\frac{x ^{2} + 5 x + 6}{x + 3}

x - 2 - 2

What is the domain of f(x)=sqrt(((1-x))/x) ?
The domain of f(x)=sqrt(((1-x))/x) is 0<x<= 1