What is the domain of 1/(sqrt(t+2))+sqrt(t+1)+t ?

The domain of 1/(sqrt(t+2))+sqrt(t+1)+t is t>=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(t+2))+sqrt(t+1)+t

domain

\frac{1}{t + 2} + t + 1 + t

t \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 1

Find undefined (singularity) points:

t = - 2

Combine real regions and undefined points for final function domain

t \geq - 1

\frac{x ^{2}}{x - 8}

f (x) = \frac{x}{x ^{2} - 5 x}

\frac{8}{5 + x}

f (x) = \frac{2 ^{x}}{2 + 2 ^{x}}

e^{x} - 1

What is the domain of 1/(sqrt(t+2))+sqrt(t+1)+t ?
The domain of 1/(sqrt(t+2))+sqrt(t+1)+t is t>=-1