What is the domain of x/(sqrt(x^2+1)) ?

The domain of x/(sqrt(x^2+1)) is -infinity <x<infinity

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domain of x/(sqrt(x^2+1))

domain

\frac{x}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

sin (\frac{2}{x}) + 1

ln (t)

\frac{x ^{2} - 16}{4 x + 5}

\frac{x ^{2} - 49}{x ^{2} - 81}

\frac{5 x}{7 x - 1}

What is the domain of x/(sqrt(x^2+1)) ?
The domain of x/(sqrt(x^2+1)) is -infinity <x<infinity