What is the domain of f(x)=ln(12-5x^2) ?

The domain of f(x)=ln(12-5x^2) is -(2sqrt(3))/(sqrt(5))<x<(2sqrt(3))/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=ln(12-5x^2)

domain

f (x) = ln (12 - 5 x^{2})

- \frac{2 3}{5} < x < \frac{2 3}{5}

Interval Notation

(- \frac{2 3}{5}, \frac{2 3}{5})

Solution steps

Find positive values for logs:

- \frac{2 3}{5} < x < \frac{2 3}{5}

The function domain

- \frac{2 3}{5} < x < \frac{2 3}{5}

y = ln (ln (3 x - 14))

y = 3 tan (x)

y = \frac{x ^{2} + x - 38}{x ^{2} - 25}

\frac{x ^{2} + 6 x + 5}{x ^{2} - 25}

h (x) = ln (x + 3)

What is the domain of f(x)=ln(12-5x^2) ?
The domain of f(x)=ln(12-5x^2) is -(2sqrt(3))/(sqrt(5))<x<(2sqrt(3))/(sqrt(5))