What is the domain of sqrt((x^2-x-20)/(x^2-x+2)) ?

The domain of sqrt((x^2-x-20)/(x^2-x+2)) is x = 5

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domain of sqrt((x^2-x-20)/(x^2-x+2))

domain

\frac{x ^{2} - x - 20}{x ^{2} - x + 2}

x \leq - 4 or x \geq 5

Interval Notation

(- \infty, - 4] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 5

The function domain

x \leq - 4 or x \geq 5

f (x) = \frac{x ^{2}}{3 - x}

lo g_{10} (4 x - x^{2})

f (x) = \frac{x}{3 x - 6}

f (x) = \frac{( x - 2 ) ( x + 5 )}{x + 2}

\frac{x ^{2} - 100}{x ^{2} + x - 90}

What is the domain of sqrt((x^2-x-20)/(x^2-x+2)) ?
The domain of sqrt((x^2-x-20)/(x^2-x+2)) is x<=-4\lor x>= 5