What is the domain of f(x)= x/((x^2+1)) ?

The domain of f(x)= x/((x^2+1)) is -infinity <x<infinity

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domain of f(x)= x/((x^2+1))

domain

f (x) = \frac{x}{( x ^{2} + 1 )}

- \infty < x < \infty

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{2 + 3 x}{x - 1}

f (x) = 4 sin (2 x + 5) - 7

f (x) = \frac{x - 2}{3 x ^{2} + x - 2}

\frac{8 x - 8}{x + 2}

2^{- x} - 1

What is the domain of f(x)= x/((x^2+1)) ?
The domain of f(x)= x/((x^2+1)) is -infinity <x<infinity