What is the domain of f(x)=((2x^2-6x+4)/(-3x-5)) ?

The domain of f(x)=((2x^2-6x+4)/(-3x-5)) is x -5/3

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domain of f(x)=((2x^2-6x+4)/(-3x-5))

domain

f (x) = (\frac{2 x ^{2} - 6 x + 4}{- 3 x - 5})

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

f (x) = e^{- 2 x} - 3

14 - x

arcsin (ln (x))

\frac{- 6 x - 49}{7 x + 29}

f (x) = lo g_{10} (4 - x)

What is the domain of f(x)=((2x^2-6x+4)/(-3x-5)) ?
The domain of f(x)=((2x^2-6x+4)/(-3x-5)) is x<-5/3 \lor x>-5/3