What is the domain of f(x)=log_{2}(x+1)+log_{2}(x-1) ?

The domain of f(x)=log_{2}(x+1)+log_{2}(x-1) is x>1

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domain of f(x)=log_{2}(x+1)+log_{2}(x-1)

domain

f (x) = lo g_{2} (x + 1) + lo g_{2} (x - 1)

x > 1

Solution steps

Find positive values for logs:

x > 1

The function domain

x > 1

f (x) = \frac{2 x}{x - 5}

f (x) = x^{3} + x

f (x) = \frac{x + 3}{( x + 2 ) ( x - 5 )}

f (x) = - \frac{2}{3}

x^{\frac{5}{3}} - 5 x^{\frac{2}{3}}

What is the domain of f(x)=log_{2}(x+1)+log_{2}(x-1) ?
The domain of f(x)=log_{2}(x+1)+log_{2}(x-1) is x>1