What is the domain of f(x)=(x^2-16)^{1/2} ?

The domain of f(x)=(x^2-16)^{1/2} is x = 4

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domain of f(x)=(x^2-16)^{1/2}

domain

f (x) = (x^{2} - 16)^{\frac{1}{2}}

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

f (x) = \frac{3 x}{4 - x}

- 6 \cdot \frac{1}{cos ( 5 )} (y + π) + 5

f (x) = 4 - 7 t

f (x) = 2 x^{2} - 3 x + 4

3 x - 10

What is the domain of f(x)=(x^2-16)^{1/2} ?
The domain of f(x)=(x^2-16)^{1/2} is x<=-4\lor x>= 4