What is the domain of f(x)=(6x-1)/(x^2+1) ?

The domain of f(x)=(6x-1)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(6x-1)/(x^2+1)

domain

f (x) = \frac{6 x - 1}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

4 x^{2}

f (x) = x^{3} - 2 x + 1

f (x) = - (x - 1)^{2} + 4

f (x) = - (x - 1)^{2} + 1

y = 1 0^{x}

What is the domain of f(x)=(6x-1)/(x^2+1) ?
The domain of f(x)=(6x-1)/(x^2+1) is -infinity <x<infinity