What is the domain of f(x)=(sqrt(-x+1))/(x^2-1) ?

The domain of f(x)=(sqrt(-x+1))/(x^2-1) is x<-1\lor-1<x<1

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domain of f(x)=(sqrt(-x+1))/(x^2-1)

domain

f (x) = \frac{- x + 1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1)

Solution steps

Find non-negative values for radicals:

x \leq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or - 1 < x < 1

- x + 7

f (x) = ln (25 x - x^{2})

f (x) = \frac{5 - 2 x}{x ^{2} - 3 x + 2}

lo g_{10} (x - 2) - 5

\frac{2 x ^{2} + 10 x - 12}{x ^{2} + x - 6}

What is the domain of f(x)=(sqrt(-x+1))/(x^2-1) ?
The domain of f(x)=(sqrt(-x+1))/(x^2-1) is x<-1\lor-1<x<1