What is the domain of log_{10}(16x-x^2) ?

The domain of log_{10}(16x-x^2) is 0<x<16

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domain of log_{10}(16x-x^2)

domain

lo g_{10} (16 x - x^{2})

0 < x < 16

Interval Notation

(0, 16)

Solution steps

Find positive values for logs:

0 < x < 16

The function domain

0 < x < 16

x^{2} - 6 x + 18

x^{2} - 6 x + 10

f (x) = 2 x + 4

1 - x + 1

\frac{x ^{2} + x - 12}{x ^{2} - 4}

What is the domain of log_{10}(16x-x^2) ?
The domain of log_{10}(16x-x^2) is 0<x<16