What is the domain of (x^2+7x-18)/((x+1)(x-3)(x+9)) ?

The domain of (x^2+7x-18)/((x+1)(x-3)(x+9)) is x 3

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domain of (x^2+7x-18)/((x+1)(x-3)(x+9))

domain

\frac{x ^{2} + 7 x - 18}{( x + 1 ) ( x - 3 ) ( x + 9 )}

x < - 9 or - 9 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 9) \cup (- 9, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3, x = - 9

The function domain

x < - 9 or - 9 < x < - 1 or - 1 < x < 3 or x > 3

f (x) = x^{2} + 6 x - 27

f (t) = \frac{4}{3 - t}

- 3 sin (2 u + 3.1416)

f (x) = - \frac{1}{x - 3} + 1

\frac{x ^{2} - 1}{x ^{2} - 49}

What is the domain of (x^2+7x-18)/((x+1)(x-3)(x+9)) ?
The domain of (x^2+7x-18)/((x+1)(x-3)(x+9)) is x<-9\lor-9<x<-1\lor-1<x<3\lor x>3