What is the domain of f(x)=(3x-2)/(3x+1) ?

The domain of f(x)=(3x-2)/(3x+1) is x -1/3

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domain of f(x)=(3x-2)/(3x+1)

domain

f (x) = \frac{3 x - 2}{3 x + 1}

x < - \frac{1}{3} or x > - \frac{1}{3}

Interval Notation

(- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{3}

The function domain

x < - \frac{1}{3} or x > - \frac{1}{3}

f (x) = \frac{3}{2 x ^{2} + x + 2}

f (x) = - (x - 2)^{2} + 1

f (x) = 0. 4^{(5 - x)} - 4

\frac{3 x - 5}{x - 2}

\frac{x ^{2}}{2}

What is the domain of f(x)=(3x-2)/(3x+1) ?
The domain of f(x)=(3x-2)/(3x+1) is x<-1/3 \lor x>-1/3