What is the shift f(t)= 1/3 cos(-t-pi/6)+2 ?

The shift f(t)= 1/3 cos(-t-pi/6)+2 is Phase:-pi/6 , Vertical:2

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shift f(t)= 1/3 cos(-t-pi/6)+2

shift

f (t) = \frac{1}{3} cos (- t - \frac{π}{6}) + 2

Phase : - \frac{π}{6}, Vertical : 2

Solution steps

f (x) = \frac{1}{3} cos (- t - \frac{π}{6}) + 2

g (B x - C) = cos (- t - \frac{π}{6}), B = - 1, C = \frac{π}{6}, D = 2

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{6}}{- 1}

- \frac{π}{6}

The vertical shift

D

2

2

- 3 y - 6 x = 6

\frac{4 x}{3 x - 10}

f (x) = \frac{x ^{2} - 9}{3 x - 9}

f (x) = - 2 (x - 1)^{3} + 5

9 x - 8 y - 24 = 0

What is the shift f(t)= 1/3 cos(-t-pi/6)+2 ?
The shift f(t)= 1/3 cos(-t-pi/6)+2 is Phase:-pi/6 , Vertical:2