What is the domain of f(x)=sqrt(3x^2-3) ?

The domain of f(x)=sqrt(3x^2-3) is x = 1

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domain of f(x)=sqrt(3x^2-3)

domain

f (x) = 3 x^{2} - 3

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = x^{2} + 8 x + 12

f (x) = - 3 x - 12

f (x) = lo g_{3} (2 x - 4)

f (x) = x - 7 + 3

f (x) = e^{\frac{- x}{2}}

What is the domain of f(x)=sqrt(3x^2-3) ?
The domain of f(x)=sqrt(3x^2-3) is x<=-1\lor x>= 1