What is the domain of f(x)=x^2+4,x>= 0 ?

The domain of f(x)=x^2+4,x>= 0 is x>= 0

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domain of f(x)=x^2+4,x>= 0

domain

f (x) = x^{2} + 4, x \geq 0

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Set the domain to the given interval

x \geq 0

The function has no undefined points nor domain constraints. Therefore, the domain is

x \geq 0

f (x) = \frac{x ^{2} - 3 x - 4}{x - 2}

f (x) = \frac{4 - 3 x}{x - 5}

f (x) = ln (\frac{3 x - 2}{x + 4})

f (x) = (x - 1)

f (x) = - x^{3} + 3 x^{2} - 2

What is the domain of f(x)=x^2+4,x>= 0 ?
The domain of f(x)=x^2+4,x>= 0 is x>= 0