What is the domain of f(x)=(2x-5)/(-5x+37) ?

The domain of f(x)=(2x-5)/(-5x+37) is x 37/5

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domain of f(x)=(2x-5)/(-5x+37)

domain

f (x) = \frac{2 x - 5}{- 5 x + 37}

x < \frac{37}{5} or x > \frac{37}{5}

Interval Notation

(- \infty, \frac{37}{5}) \cup (\frac{37}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{37}{5}

The function domain

x < \frac{37}{5} or x > \frac{37}{5}

f (x) = lo g_{3} (4 \cdot 3^{x - 1} - 1)

\frac{x + 4}{x + 6}

f (x) = 18 - 3 x

\frac{x + 2}{x - 9}

arccos (\frac{1}{x - 3})

What is the domain of f(x)=(2x-5)/(-5x+37) ?
The domain of f(x)=(2x-5)/(-5x+37) is x< 37/5 \lor x> 37/5