What is the domain of (sqrt(x-2))/(x^2-9) ?

The domain of (sqrt(x-2))/(x^2-9) is 2 3

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domain of (sqrt(x-2))/(x^2-9)

domain

\frac{x - 2}{x ^{2} - 9}

2 \leq x < 3 or x > 3

Interval Notation

[2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

2 \leq x < 3 or x > 3

f (x) = 3 - t - 2 + t

3^{x} + 1

∣ x - 4 ∣ + 2

\frac{3 x ^{2}}{x + 5}

9 x + 8

What is the domain of (sqrt(x-2))/(x^2-9) ?
The domain of (sqrt(x-2))/(x^2-9) is 2<= x<3\lor x>3