What is the domain of f(x)= 2/(sqrt(5-2x)) ?

The domain of f(x)= 2/(sqrt(5-2x)) is x< 5/2

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domain of f(x)= 2/(sqrt(5-2x))

domain

f (x) = \frac{2}{5 - 2 x}

x < \frac{5}{2}

Interval Notation

(- \infty, \frac{5}{2})

Solution steps

Find non-negative values for radicals:

x \leq \frac{5}{2}

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

x < \frac{5}{2}

f (x) = - 4^{x} + 2

\frac{x - 1 - 1}{x - 1 + 1}

f (x) = \frac{4 x}{x ^{2} - 1}

f (x) = ∣ x + 2 ∣ - 1

9^{x}

What is the domain of f(x)= 2/(sqrt(5-2x)) ?
The domain of f(x)= 2/(sqrt(5-2x)) is x< 5/2