What is the domain of h(x)=sqrt(x-1) ?

The domain of h(x)=sqrt(x-1) is x>= 1

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domain of h(x)=sqrt(x-1)

domain

h (x) = x - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{( 2 x + 3 )}{( x ^{2} + 3 x + 2 )}

f (x) = \frac{x ^{2} + x - 1}{x ^{2}}

f (x) = 2 x^{2} - x + 1

\frac{8 x - 24}{x ^{2} - x - 20}

\frac{x ^{2} - 9}{x ^{2} - 16}