What is the domain of f(x)=-3-sqrt(4x-12) ?

The domain of f(x)=-3-sqrt(4x-12) is x>= 3

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domain of f(x)=-3-sqrt(4x-12)

domain

f (x) = - 3 - 4 x - 12

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

\frac{1}{9 - x - 3}

f (x) = x^{2} - x + 6 + 1

\frac{x - 6}{x ^{2} - 16}

f (x) = \frac{x - 3}{x - 5}

\frac{8 x}{x ^{2} - 25}

What is the domain of f(x)=-3-sqrt(4x-12) ?
The domain of f(x)=-3-sqrt(4x-12) is x>= 3