What is the domain of 1/(x^2-5) ?

The domain of 1/(x^2-5) is x sqrt(5)

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domain of 1/(x^2-5)

domain

\frac{1}{x ^{2} - 5}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = lo g_{2} (x^{2} - 16)

f (x) = e^{(x^{2} - 3)}

f (x) = (x + 2)^{3} - 1

f (x) = \frac{5}{1 - e ^{1 - x^{2}}}

f (x) = - \frac{3}{x - 3}

What is the domain of 1/(x^2-5) ?
The domain of 1/(x^2-5) is x<-sqrt(5)\lor-sqrt(5)<x<sqrt(5)\lor x>sqrt(5)