What is the domain of f(x)=sqrt((x^2+1)/(x+3)) ?

The domain of f(x)=sqrt((x^2+1)/(x+3)) is x>-3

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domain of f(x)=sqrt((x^2+1)/(x+3))

domain

f (x) = \frac{x ^{2} + 1}{x + 3}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find non-negative values for radicals:

x > - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

f (x) = x (x^{2} + 1)

f (x) = \frac{e ^{x}}{1 + e ^{x}}

\frac{1}{1 + e ^{x}}

lo g_{6} (2 x - 4)

f (x) = \frac{x ^{2} - 1}{x ^{2} - 3}

What is the domain of f(x)=sqrt((x^2+1)/(x+3)) ?
The domain of f(x)=sqrt((x^2+1)/(x+3)) is x>-3