What is the domain of f(x)=log_{2}(x+1)-3 ?

The domain of f(x)=log_{2}(x+1)-3 is x>-1

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domain of f(x)=log_{2}(x+1)-3

domain

f (x) = lo g_{2} (x + 1) - 3

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

x - 2 + 4 - x

f (x) = \frac{x}{2 x ^{2} - 6 x + 4}

f (x) = (x + 1) 2

f (x) = \frac{1}{x - 1}

y = \frac{3}{x + 2}

What is the domain of f(x)=log_{2}(x+1)-3 ?
The domain of f(x)=log_{2}(x+1)-3 is x>-1