What is the domain of f(x)= 1/(x^2-x-12) ?

The domain of f(x)= 1/(x^2-x-12) is x 4

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domain of f(x)= 1/(x^2-x-12)

domain

f (x) = \frac{1}{x ^{2} - x - 12}

x < - 3 or - 3 < x < 4 or x > 4

Interval Notation

(- \infty, - 3) \cup (- 3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 3

The function domain

x < - 3 or - 3 < x < 4 or x > 4

f (x) = (\frac{x + 3}{x - 1})

4 - x^{2} + \frac{x + 2}{11 - x}

f (x) = e^{s i n (\frac{π}{x})}

y = \frac{x ^{2} - 1}{x ^{3} + x}

f (x) = x^{3} + x^{2}

What is the domain of f(x)= 1/(x^2-x-12) ?
The domain of f(x)= 1/(x^2-x-12) is x<-3\lor-3<x<4\lor x>4