What is the domain of f(x)=x+x/(x^2-1) ?

The domain of f(x)=x+x/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=x+x/(x^2-1)

domain

f (x) = x + \frac{x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

1 + \frac{2}{x}

f (x) = \frac{1}{6 - 2 x - x ^{2}}

f (x) = (x - 2)^{3} (3 x + 14)

lo g_{3} (x - 3)

\frac{5}{x - 3}

What is the domain of f(x)=x+x/(x^2-1) ?
The domain of f(x)=x+x/(x^2-1) is x<-1\lor-1<x<1\lor x>1