What is the domain of f(x)=sqrt(x^2-3x-40) ?

The domain of f(x)=sqrt(x^2-3x-40) is x = 8

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domain of f(x)=sqrt(x^2-3x-40)

domain

f (x) = x^{2} - 3 x - 40

x \leq - 5 or x \geq 8

Interval Notation

(- \infty, - 5] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 8

The function domain

x \leq - 5 or x \geq 8

f (x) = x + 4

f (x) = x^{3} - 3 x^{2} + 3 x - 5

(- 2, 0), (5, - 8)

f (x) = lo g_{2} (x - 2)

x + 12 y = 4

What is the domain of f(x)=sqrt(x^2-3x-40) ?
The domain of f(x)=sqrt(x^2-3x-40) is x<=-5\lor x>= 8