What is the domain of f(x)=(x/(x+8))/(x/(x+8)+8) ?

The domain of f(x)=(x/(x+8))/(x/(x+8)+8) is x -64/9

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domain of f(x)=(x/(x+8))/(x/(x+8)+8)

domain

f (x) = \frac{\frac{x}{x + 8}}{\frac{x}{x + 8} + 8}

x < - 8 or - 8 < x < - \frac{64}{9} or x > - \frac{64}{9}

Interval Notation

(- \infty, - 8) \cup (- 8, - \frac{64}{9}) \cup (- \frac{64}{9}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{64}{9}, x = - 8

The function domain

x < - 8 or - 8 < x < - \frac{64}{9} or x > - \frac{64}{9}

3 e^{x}

y = x - 10

f (x) = \frac{∣ x ∣ - 2}{x ^{2} - 2 x - 3}

g (x) = \frac{x - 8}{x - 4}

f (x) = 12 - x + 3

What is the domain of f(x)=(x/(x+8))/(x/(x+8)+8) ?
The domain of f(x)=(x/(x+8))/(x/(x+8)+8) is x<-8\lor-8<x<-64/9 \lor x>-64/9