What is the domain of f(x)=sqrt(x^2+6x+9) ?

The domain of f(x)=sqrt(x^2+6x+9) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+6x+9)

domain

f (x) = x^{2} + 6 x + 9

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x - 7

f (x) = lo g_{10} (x^{2} - 4 x + 20)

f (x) = \frac{9 + 5 x}{x ^{2} - 16}

f (x) = \frac{x + 5}{3 x ^{2} + 10 x + 3}

f (x) = \frac{8}{x ^{2} - 4}

What is the domain of f(x)=sqrt(x^2+6x+9) ?
The domain of f(x)=sqrt(x^2+6x+9) is -infinity <x<infinity