What is the domain of f(x)=(x-1)/(x^2+9) ?

The domain of f(x)=(x-1)/(x^2+9) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-1)/(x^2+9)

domain

f (x) = \frac{x - 1}{x ^{2} + 9}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - x^{4} + x^{3} + 9 x

f (x) = lo g_{10} (2 x)

f (x) = (x^{2} - 3) e^{x}

\frac{x ^{2} + 2 x}{x ^{2} + 5 x + 6}

What is the domain of f(x)=(x-1)/(x^2+9) ?
The domain of f(x)=(x-1)/(x^2+9) is -infinity <x<infinity