What is the domain of f(x)=sqrt(3/(2x-18)) ?

The domain of f(x)=sqrt(3/(2x-18)) is x>9

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domain of f(x)=sqrt(3/(2x-18))

domain

f (x) = \frac{3}{2 x - 18}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x > 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

f (x) = \frac{8 cos ( x )}{1 - sin ( x )}

y = \frac{2}{( x - 3 ) ( x - 8 )}

- (1.1)^{x} + 1

∣ x ∣ + 2 x - 3

4 x + 8

What is the domain of f(x)=sqrt(3/(2x-18)) ?
The domain of f(x)=sqrt(3/(2x-18)) is x>9