What is the domain of y=sqrt(2x-6)-1 ?

The domain of y=sqrt(2x-6)-1 is x>= 3

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domain of y=sqrt(2x-6)-1

domain

y = 2 x - 6 - 1

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

\frac{x - 3}{x ^{2} + 5 x}

2^{x} + 2

10 x - 2

\frac{x ^{2}}{4} - 3

f (x) = \frac{x ^{2} + 3 x}{x ^{2} - 9}