What is the domain of y= 1/(x^2-4) ?

The domain of y= 1/(x^2-4) is x 2

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domain of y= 1/(x^2-4)

domain

y = \frac{1}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = x^{2} - 4 x + 4

- 3 + ln (x)

y = \frac{1}{x ^{2} - x}

\frac{x ^{2} - 4 x - 1}{7}

\frac{3 - 3 x}{x ^{2} - 2 x + 1}

What is the domain of y= 1/(x^2-4) ?
The domain of y= 1/(x^2-4) is x<-2\lor-2<x<2\lor x>2