What is the domain of f(x)=(sqrt(x-3))/(x^2-49) ?

The domain of f(x)=(sqrt(x-3))/(x^2-49) is 3 7

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domain of f(x)=(sqrt(x-3))/(x^2-49)

domain

f (x) = \frac{x - 3}{x ^{2} - 49}

3 \leq x < 7 or x > 7

Interval Notation

[3, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

3 \leq x < 7 or x > 7

lo g_{2} (x + 4)

g (x) = \frac{3}{x ^{2} - 2 x - 15}

- 4 n \cdot \frac{x ln ( x )}{1 - x}

g (x) = 5 - x + 1

arcsin (2 x)

What is the domain of f(x)=(sqrt(x-3))/(x^2-49) ?
The domain of f(x)=(sqrt(x-3))/(x^2-49) is 3<= x<7\lor x>7